10x^2+32x=32

Solution for 10x^2+32x=32 equation:

10x^2+32x=32

We move all terms to the left:

10x^2+32x-(32)=0

a = 10; b = 32; c = -32;
Δ = b2-4ac
Δ = 322-4·10·(-32)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-48}{2*10}=\frac{-80}{20}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+48}{2*10}=\frac{16}{20}
=4/5
$